∠1∠1 and ∠2∠2 are a linear pair, and ∠2∠2 and ∠3∠3 are vertical angles. m∠2=(5+4y)∘m∠2=(5+4y)∘ and m∠3=(6y−25)∘m∠3=(6y−25)∘ . What is m∠1m∠1 ?
Accepted Solution
A:
Linear pair of angles ads up to 180°. Vertical angles have same value. According to this we have: m<1 + m<2 = 180° m<2=m<3
We can use this to solve for m<1. m<2=m<3 5+4y=6y-25 4y-6y=-25-5 -2y=-30 y=15 m<2=5+4*15 m<2=65°